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cmd.CommandText = _ "SELECT Orderid, Orderdate FROM Orders " & _ "WHERE orderdate=(SELECT MAX(orderdate) FROM orders)" cmd.Connection = cn dr = cmd.ExecuteReader If dr.HasRows Then Do While dr.Read lstResults.Items.Add(dr.Item("OrderID").ToString + " " + _ dr.Item("Orderdate").ToString) intCount += 1 Loop MessageBox.Show(intCount.ToString & " rows qualified") Else MessageBox.Show("no rows returned") End If dr.Close() cn.Close() C# OleDbConnection cn = new OleDbConnection( "Provider=Microsoft.jet.oledb.4.0;Data Source=Northwind.mdb"); OleDbDataReader dr; Int16 intCount = 0; cn.Open(); OleDbCommand cmd = new OleDbCommand(); cmd.CommandText = "SELECT Orderid, Orderdate FROM Orders " + "WHERE orderdate = (SELECT MAX(orderdate) FROM orders)"; cmd.Connection = cn; dr = cmd.ExecuteReader(); if (dr.HasRows) { while (dr.Read()) { lstResults.Items.Add (dr.GetInt32(dr.GetOrdinal("OrderID")) + " " + dr.GetDateTime(dr.GetOrdinal("Orderdate"))); intCount += 1; } MessageBox.Show(intCount + " rows qualified"); } else { MessageBox.Show("no rows returned"); } dr.Close(); cn.Close();

+ ~ _

Percent 226% 215% 157% 115% 84% 40% 33% 19% 10% 17% 40% 44%

Z =

+ ~ _

Recall that in DC circuits, given a xed equivalent source, maximum power is transferred to a resistive load when the latter is equal to the internal resistance of the source; achieving an analogous maximum power transfer condition in an AC circuit is referred to as impedance matching Consider the general form of

an AC circuit, shown in Figure 742, and assume that the source impedance, ZS , is given by ZS = RS + j XS (742)

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6. Compile, test, debug, and run your new application. 7. Now open the Database Explorer window. Use the existing connection you created earlier in this chapter to access the same database (see Exercise 8-1) and display the SQL pane in the Database Explorer window. 8. You will enter a new row into the Orders table using a SQL statement. This row will have an OrderDate column equal to today s date so it will show up in your query to return most recent orders. Erase whatever value is in the SQL pane and type the following SQL Insert statement into the SQL pane: INSERT INTO Orders (orderid, customerid, employeeid, orderdate, requireddate, shipvia ) VALUES (77777, 'BONAP', 7, Now, Now+2, 2)

~ + VS ~ _

ZS + ~ VL _

Appendix A:

The problem of interest is often that of selecting the load resistance and reactance that will maximize the real (average) power absorbed by the load Note that the requirement is to maximize the real power absorbed by the load Thus, the problem can be restated by expressing the real load power in terms of the impedance of the source and load The real power absorbed by the load is L PL = VL IL cos = Re (VL I ) where VL = and L I = VS ZS + Z L

(743)

ZL VS ZS + Z L V S (ZS + ZL )

Note The Now function is specific to Microsoft Access. It returns today s date. Now+2 would insert today s

(744)

(745)

The FiSMA projects all report size in adjusted function points only As with the NESMA projects, smaller projects are more common, but there appears at the moment to be a broader spread than with the IFPUG or COSMIC approaches Size ranges from 6 to 9,390 AFPs The median size is 235 AFPs For enhancement projects, the range is 6 to 1,843 AFPs with a median of 142 AFPs For new developments, the range is 18 to 9,390 AFPs with a median of 320 AFPs

Thus, the complex load power is given by L SL = VL I = V V2 Z L VS S S = ZL ZS + Z L (ZS + ZL ) |ZS + ZL |2 V2 S |ZS + ZL |2 (746)

and the average (real) power by L PL = Re (VL I ) = Re = = Re (ZL ) (747)

The expression for PL is maximized by selecting appropriate values of RL and XL ; it can be shown that the average power is greatest when RL = RS and XL = XS , that is, when the load impedance is equal to the complex conjugate of the source impedance, as shown in the following equation:

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